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3+2x-0.25x^2=0
a = -0.25; b = 2; c = +3;
Δ = b2-4ac
Δ = 22-4·(-0.25)·3
Δ = 7
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{7}}{2*-0.25}=\frac{-2-\sqrt{7}}{-0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{7}}{2*-0.25}=\frac{-2+\sqrt{7}}{-0.5} $
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